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100000(x^2)+1.5x-1.5=0
a = 100000; b = 1.5; c = -1.5;
Δ = b2-4ac
Δ = 1.52-4·100000·(-1.5)
Δ = 600002.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.5)-\sqrt{600002.25}}{2*100000}=\frac{-1.5-\sqrt{600002.25}}{200000} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.5)+\sqrt{600002.25}}{2*100000}=\frac{-1.5+\sqrt{600002.25}}{200000} $
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